document.write( "Question 540215: Five times a number minus twice another number equals twenty-two. The sum of the numbers is three. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #353739 by ankor@dixie-net.com(22740)\"\" \"About 
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( "Five times a number minus twice another number equals twenty-two.
\n" ); document.write( " 5x - 2y = 22
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\n" ); document.write( "The sum of the numbers is three.
\n" ); document.write( "x + y = 3
\n" ); document.write( "y = (3-x); use this form for substitution
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\n" ); document.write( "Substitute (3-x) for y in the 1st equation
\n" ); document.write( "5x - 2(3-x) = 22
\n" ); document.write( "5x - 6 + 2x = 22; you have to change the sign of -x when you mult it by -2
\n" ); document.write( "5x + 2x = 22 + 6
\n" ); document.write( "7x = 28
\n" ); document.write( "x = 28/7
\n" ); document.write( "x = 4
\n" ); document.write( "find y
\n" ); document.write( "y = 3 - 4
\n" ); document.write( "y = -1
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\n" ); document.write( "Our solution, x=4, y =-1
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\n" ); document.write( "Check these solutions in the 1st statement:
\n" ); document.write( "Five times a number minus twice another number equals twenty-two.
\n" ); document.write( "5(4) - 2(-1) =
\n" ); document.write( "20 + 2 = 22; confirms our solutions \n" ); document.write( "
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