document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=540498>Question 540498</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A lawn can be mowed at an average rate of 44 square feet per minute. What is the rate of square yards per second.     How do I solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353733 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 44 square feet /minute\r<BR>\n" );
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document.write( "9sq.ft = 1sq.yard\r<BR>\n" );
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document.write( "(44/9) sq. yards\r<BR>\n" );
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document.write( "1 minute = 60 seconds\r<BR>\n" );
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document.write( "(44/9)/60\r<BR>\n" );
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document.write( "44/9 **1/60\r<BR>\n" );
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document.write( "=44/540<BR>\n" );
document.write( "=0.08sq.yard/second </SPAN>\n" );
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