document.write( "Question 540495: This was my innitial problem;
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document.write( "\"The are of a rectangle is 165 ft^2. The Length is 4 ft greater than the width. Find the dimensions of the rectangle.\"\r
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document.write( "This my question;\r
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document.write( "After you simplify the word problem into a Quadratic Equation (the process below)..\r
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document.write( "W*L=165, L=W+4
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document.write( "W(W+4)=165
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document.write( "W^2+4W-165=0\r
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document.write( "How do you find this next part;\r
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document.write( "(W-11)(W+15)=0
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document.write( "W-11=0\r
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document.write( "How did the tutor figure 11 and 15? Is it because of the factoring? Perfect squares? Please help.\r
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Algebra.Com's Answer #353729 by mananth(16946)![]() ![]() You can put this solution on YOUR website! width = x \n" ); document.write( "length = x+4\r \n" ); document.write( "\n" ); document.write( "x(x+4)=165 \n" ); document.write( "x^2+4x-165=0\r \n" ); document.write( "\n" ); document.write( "Split the middle term such that when you add the split terms you get -4 \n" ); document.write( "and when you multiply you get -165 \n" ); document.write( "Take the prime factors of 165 \n" ); document.write( "3*5*11\r \n" ); document.write( "\n" ); document.write( "3*5 = 15 \n" ); document.write( "you need 4\r \n" ); document.write( "\n" ); document.write( "+15-11=-4\r \n" ); document.write( "\n" ); document.write( "x^2+15x-11x-165=0 \n" ); document.write( "x(x+15)-11(x+15)=0 \n" ); document.write( "(x+15)(x-11)=0 \n" ); document.write( "take the positive value since width cannot be negative\r \n" ); document.write( "\n" ); document.write( "x=11 \n" ); document.write( "length= 11+4=15\r \n" ); document.write( "\n" ); document.write( "Thats how your teacher got 11 & 15\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |