document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=540486>Question 540486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13cm, find the other two side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353713 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let base be x<BR>\n" );
document.write( "height = x-7\r<BR>\n" );
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document.write( "hypotenuse = 13\r<BR>\n" );
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document.write( "By Pythagoras theorem<BR>\n" );
document.write( "leg1^2+leg2^2=13^2\r<BR>\n" );
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document.write( "x^2+(x-7)^2=169<BR>\n" );
document.write( "x^2+x^2-14x+49=169<BR>\n" );
document.write( "2x^2-14x-120=0\r<BR>\n" );
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document.write( "/2<BR>\n" );
document.write( "x^2-7x-60=0<BR>\n" );
document.write( "x^2-12x+5x-60=0<BR>\n" );
document.write( "x(x-12)+5(x-12)=0<BR>\n" );
document.write( "(x-12)(x+5)=0<BR>\n" );
document.write( "Take the positive root\r<BR>\n" );
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document.write( "One leg =12 <BR>\n" );
document.write( "Other = 12-7=5<BR>\n" );
document.write( "The sides are 5,12 & 13\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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