document.write( "Question 540310: I am given the equation 4^x+4=5^2x+5 and I have to answer it in the form of a log. My professor did not go over something like this so I have no idea on where to start the problem. \n" ); document.write( "
Algebra.Com's Answer #353693 by bucky(2189) ![]() You can put this solution on YOUR website! You are given to solve for x: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Any time you have an unknown in the exponent, one of the things you should think of is using logarithms. Logarithms have a very useful property for such problems. . \n" ); document.write( "Let's take the logarithm of both sides. We'll use logarithms to the base 10, but we could use natural logs as well. Taking the logarithm of both sides results in: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "A useful property of logarithms is that exponents can be brought out as the multiplier of the logarithm operator. Bringing these two logarithms out as multipliers results in the equation becoming: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Note that \n" ); document.write( ". \n" ); document.write( "Similarly \n" ); document.write( ". \n" ); document.write( "Substitute these two values into the log equation to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "From here on out, its a fairly straightforward algebra problem. \n" ); document.write( ". \n" ); document.write( "Do the distributed multiplication on the left side by multiplying 0.602056 times each of the two terms in the parentheses to make the left side become as shown below: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The 4 times 0.602056 multiplies out to 2.408224 and the equation simplifies to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Next, follow the same procedure of distributed multiplication on the right side. Multiply 0.698970 times each of the two terms in parentheses to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Move the constant from the left side by subtracting 2.408224 from both sides. (On the right side the 3.494850 has 2.408224 subtracted from it.) The equation then is simplified to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Then transfer the 1.397940x from the right side to the left side by subtracting 1.397940x from both sides. The equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Solve for x by dividing both sides by -0.795884 to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and this equals: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Let's try this in the original problem to see if it checks. \n" ); document.write( ". \n" ); document.write( "Start with: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Substitute -1.365607 for x: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Algebraically simplify the two exponents: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The exponent on the right side sums to give: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Use a scientific calculator with an \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Pretty close to equal on both sides. The round off errors of the logarithms cause some differences. And I could have made some fat-fingered keying errors on the calculator also. Check my work. This near equality tells us that the value of x is accurate within a \"reasonable\" amount. \n" ); document.write( ". \n" ); document.write( "[A little closer value of x (by carrying more decimal places on a calculator) is x = -1.36529380395] \n" ); document.write( ". \n" ); document.write( "The process of bringing exponents outside of logarithms as multipliers is correct. Hope you can translate this discussion into an understanding of how you can handle exponents in which a variable appears. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |