document.write( "Question 540359: The sum of the reciprocals of two numbers is 16/15 and the second number is 1 larger thank the first. Find the two numbers? \n" ); document.write( "
Algebra.Com's Answer #353673 by oberobic(2304) ![]() You can put this solution on YOUR website! The two numbers can be defined as: \n" ); document.write( "x \n" ); document.write( "x+1 \n" ); document.write( ". \n" ); document.write( "so their reciprocals are: \n" ); document.write( "1/x \n" ); document.write( "1/(x+1) \n" ); document.write( ". \n" ); document.write( "1/x + 1/(x+1) = 16/15 \n" ); document.write( ". \n" ); document.write( "((x+1)+x)/(x*(x+1) = 16/15 \n" ); document.write( ". \n" ); document.write( "15((x+1)+x) = 16(x*(x+1)) \n" ); document.write( ". \n" ); document.write( "15x + 15 + 15x = 16(x^2 +x) \n" ); document.write( ". \n" ); document.write( "30x + 15 = 16x^2 +16x \n" ); document.write( ". \n" ); document.write( "0 = 16x^2 -14x -15 \n" ); document.write( ". \n" ); document.write( "16x^2 -14x -15 = 0 \n" ); document.write( ". \n" ); document.write( "(16x+10)(x-3/2) = 0 \n" ); document.write( ". \n" ); document.write( "Check with FOIL. \n" ); document.write( "16x^2 -24x +10x -15 \n" ); document.write( "Correct \n" ); document.write( ". \n" ); document.write( "So, x = -5/8 or x=3/2 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Or you could solve with quadratic equation. \n" ); document.write( ". \n" ); document.write( "
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