document.write( "Question 540371: How many liters of pure acid must be added to 5L of a solution that is 20% acid to make a solution that is 60% acid?\r
\n" ); document.write( "\n" ); document.write( "x+0.2 (5)= 0-6 (x=5)
\n" ); document.write( "x=1= o.6x+3
\n" ); document.write( "-0.6x-1-0.6x-1
\n" ); document.write( "____________________
\n" ); document.write( "0.4x=2
\n" ); document.write( "______
\n" ); document.write( "0.4 0.4
\n" ); document.write( "x=5
\n" ); document.write( "Does my work look correct?
\n" ); document.write( "

Algebra.Com's Answer #353668 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" = liters of pure acid needed
\n" ); document.write( "given:
\n" ); document.write( "\"+.2%2A5+=+1+\" liter od pure acid in 20% solution
\n" ); document.write( "\"+%28+1+%2B+x+%29+%2F+%28+5+%2B+x+%29+=+.6+\"
\n" ); document.write( "\"+1+%2B+x+=+.6%2A%28+5+%2B+x+%29+\"
\n" ); document.write( "\"+1+%2B+x++=+3+%2B+.6x+\"
\n" ); document.write( "\"+.4x+=+2+\"
\n" ); document.write( "\"+x+=+5+\"
\n" ); document.write( "5 liters of pure acid is needed
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+1+%2B+5+%29+%2F+%28+5+%2B+5+%29+=+.6+\"
\n" ); document.write( "\"+6+%2F+10+=+.6+\"
\n" ); document.write( "\"+.6+=+.6+\"
\n" ); document.write( "OK
\n" ); document.write( "----------
\n" ); document.write( "I'm not sure how you did it, but this is how
\n" ); document.write( "I do all these kind of problems. Same answer.
\n" ); document.write( "
\n" );