document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=540212>Question 540212</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of the rectangle is 2m more than the width. The area of the rectangle is 48m squared. Find the length and the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353623 by </B><A HREF=/tutors/aboutme.mpl?userid=abigal95><B>abigal95(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=abigal95><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353623\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the equation to start with is<BR>\n" );
document.write( " L x W = A<BR>\n" );
document.write( "you are given that w+2=L<BR>\n" );
document.write( "so substitute w+2 for L in the original equation and plug in the value of the area given\r<BR>\n" );
document.write( "\n" );
document.write( "w(w+2)=48\r<BR>\n" );
document.write( "\n" );
document.write( "and foil it out and subtract 48 from both sides to get\r<BR>\n" );
document.write( "\n" );
document.write( "w^2+2w-48=0\r<BR>\n" );
document.write( "\n" );
document.write( "then you will have to factor the equation which comes out to be\r<BR>\n" );
document.write( "\n" );
document.write( "(w+8)(w-6)\r<BR>\n" );
document.write( "\n" );
document.write( "the (W+8) will be set equal to 0 and w will be negative so then (W-6) will be set equal to 0 and then that equals 6 which is the width and then the length would be 8 since W+2 equals the length, and 6 times 8 is 48<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );