document.write( "Question 539735: how do I divide and write answer in standard form for (-2-3i)/i \n" ); document.write( "
Algebra.Com's Answer #353559 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! (-2-3i)/i Multiply numerator and denominator by i and we get \n" ); document.write( "(-2i-3i^2)/i^2 We know that i^2=-1, sooo \n" ); document.write( "(-2i+3)/-1 = \n" ); document.write( "2i-3 and standard form is a+bi, so we get: \n" ); document.write( "-3+2i------------------ans\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "-3+2i=?(-2-3i)/i multiply each term by i \n" ); document.write( "-3i+2i^2=?-2-3i or \n" ); document.write( "-3i-2=-2-3i \n" ); document.write( "OK\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |