document.write( "Question 539735: how do I divide and write answer in standard form for (-2-3i)/i \n" ); document.write( "
Algebra.Com's Answer #353559 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
(-2-3i)/i Multiply numerator and denominator by i and we get
\n" ); document.write( "(-2i-3i^2)/i^2 We know that i^2=-1, sooo
\n" ); document.write( "(-2i+3)/-1 =
\n" ); document.write( "2i-3 and standard form is a+bi, so we get:
\n" ); document.write( "-3+2i------------------ans\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "-3+2i=?(-2-3i)/i multiply each term by i
\n" ); document.write( "-3i+2i^2=?-2-3i or
\n" ); document.write( "-3i-2=-2-3i
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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