document.write( "Question 539707: A boat travels 3km upstream and 3km back. the time for the round trip is 10 hours. the speed of the stream is 5km/hr whats the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #353543 by mananth(16946)\"\" \"About 
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Boat speed x
\n" ); document.write( "current speed 5
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\n" ); document.write( "against current x- 5 kph
\n" ); document.write( "with current x+ 5 kph
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\n" ); document.write( "Distance= 3 km
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\n" ); document.write( "Time against + time with = 10 hours
\n" ); document.write( "t=d/r \r
\n" ); document.write( "\n" ); document.write( "3 /( x + 5 ) + 3 /(x - 5 ) = 10
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\n" ); document.write( "LCD = (x - 5 ) ( x + 5 )
\n" ); document.write( "3 *( x - 5 ) + 3 (x + 5 ) = 10
\n" ); document.write( "3 x - 15 + 3 x + 15 = 10 ( x ^2 - 25 )
\n" ); document.write( "6 x = 10 x ^2 - 250
\n" ); document.write( "10 x ^2 - -6 x - 250
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\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 10 , b= -6 , c= -250
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\n" ); document.write( "b^2-4ac= 36 + 10000
\n" ); document.write( "b^2-4ac= 10036 \"%09sqrt%28%0910036%09%29=%09100.18%09\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( 6 + 100.18 )/ 20
\n" ); document.write( "x1= 5.31
\n" ); document.write( "x2=( 6 -100.18 ) / 20
\n" ); document.write( "x2= -4.71
\n" ); document.write( "Ignore negative value
\n" ); document.write( "Boat speed = 5.31 mph \r
\n" ); document.write( "\n" ); document.write( "ma.ananth@hotmail.ca
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