document.write( "Question 539707: A boat travels 3km upstream and 3km back. the time for the round trip is 10 hours. the speed of the stream is 5km/hr whats the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #353543 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Boat speed x \n" ); document.write( "current speed 5 \n" ); document.write( " \n" ); document.write( "against current x- 5 kph \n" ); document.write( "with current x+ 5 kph \n" ); document.write( " \n" ); document.write( "Distance= 3 km \n" ); document.write( " \n" ); document.write( "Time against + time with = 10 hours \n" ); document.write( "t=d/r \r \n" ); document.write( "\n" ); document.write( "3 /( x + 5 ) + 3 /(x - 5 ) = 10 \n" ); document.write( " \n" ); document.write( "LCD = (x - 5 ) ( x + 5 ) \n" ); document.write( "3 *( x - 5 ) + 3 (x + 5 ) = 10 \n" ); document.write( "3 x - 15 + 3 x + 15 = 10 ( x ^2 - 25 ) \n" ); document.write( "6 x = 10 x ^2 - 250 \n" ); document.write( "10 x ^2 - -6 x - 250 \n" ); document.write( " \n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( " \n" ); document.write( "a= 10 , b= -6 , c= -250 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 36 + 10000 \n" ); document.write( "b^2-4ac= 10036 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 6 + 100.18 )/ 20 \n" ); document.write( "x1= 5.31 \n" ); document.write( "x2=( 6 -100.18 ) / 20 \n" ); document.write( "x2= -4.71 \n" ); document.write( "Ignore negative value \n" ); document.write( "Boat speed = 5.31 mph \r \n" ); document.write( "\n" ); document.write( "ma.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |