document.write( "Question 52910This question is from textbook algebra structure and method
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document.write( ": The gym is 21 years newer than the auditorium. the gym is also one fourth as old as the auditorium. How old is each building?\r
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document.write( "(26,27,28) possible ages for auditorium\r
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document.write( "Write an equation as well as solve. \n" );
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Algebra.Com's Answer #35354 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Human-and-algebraic-language/52910 (2006-09-19 18:07:18): The gym is 21 years newer than the auditorium. the gym is also one fourth as old as the auditorium. How old is each building? \n" ); document.write( ": \n" ); document.write( "(26,27,28) possible ages for auditorium \n" ); document.write( ": \n" ); document.write( "Write an equation as well as solve. \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "a = age of the auditorium \n" ); document.write( ": \n" ); document.write( "\"The gym is 21 years newer than the auditorium.\" \n" ); document.write( "[a-21] = age of the gym \n" ); document.write( ": \n" ); document.write( "\"the gym is one fourth as old as the auditorium.\" \n" ); document.write( "[a-21] = .25a \n" ); document.write( "a -.25a = + 21 \n" ); document.write( " .75a = 21 \n" ); document.write( " a = 21/.75 \n" ); document.write( " a = 28 years old\r \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check: Gym = 28 - 21 = 7 years, which is 1/4 of 28\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |