document.write( "Question 539725: find the equation of a line that is perpendicular to the line y=1/6x+4 and contains the point (-3,- 0) \n" ); document.write( "

Algebra.Com's Answer #353534 by mananth(16946) $\"\"$ $\"About$

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1 y = 1/ 6 x + 4
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = 1/ 6 x + 4
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = 1/6
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal -6
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be -6
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\n" ); document.write( "m= -6 ,point ( -3 , 0 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "0 = 18.00 + b
\n" ); document.write( "b= -18
\n" ); document.write( "m= -6
\n" ); document.write( "The required equation is y = -6 x-18
\n" ); document.write( "m.ananth@hotmail.ca
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