document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=539694>Question 539694</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need a little boost on this one to refresh my memory! Please!<BR>\n" );
document.write( "A coin is weighted so that tails is twice as likely as heads to occur. What probability should we assign to heads? to tail?\r<BR>\n" );
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document.write( "Thank you so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353514 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the probability of obtaining a head be p. Then the probability of getting a tail is 2p. They add up to 1 (disjoint, either must happen), so p + 2p = 1, p = 1/3 and 2p = 2/3. </SPAN>\n" );
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