document.write( "Question 539058: At noon, your family leaves Louisville on a trip to Memphis driving at 40 miles per hour. Your uncle leaves Memphis to come to Louisville 2 hours later. He is taking the same route and is driving 60 miles per hour. The two cities are 380 miles apart. At what time do the cars meet? \n" ); document.write( "
Algebra.Com's Answer #353492 by ankor@dixie-net.com(22740)\"\" \"About 
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At noon, your family leaves Louisville on a trip to Memphis driving at 40 miles per hour.
\n" ); document.write( " Your uncle leaves Memphis to come to Louisville 2 hours later.
\n" ); document.write( " He is taking the same route and is driving 60 miles per hour.
\n" ); document.write( " The two cities are 380 miles apart. At what time do the cars meet?
\n" ); document.write( ":
\n" ); document.write( "Let t = your travel time
\n" ); document.write( "then
\n" ); document.write( "(t-2) = uncle's travel time who left two hours later
\n" ); document.write( ":
\n" ); document.write( "It helps to know that the sum of the distances of the two cars equal 380 mi
\n" ); document.write( "Write a distance equation, dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "your dist + Unc's dist = 380 miles
\n" ); document.write( "40t + 60(t-2) = 380
\n" ); document.write( "40t + 60t - 120 = 380
\n" ); document.write( "40t + 60t = 380 + 120
\n" ); document.write( "100t = 500
\n" ); document.write( "t = \"500%2F100\"
\n" ); document.write( "t = 5 hrs is your travel time, you left at noon, therefore
\n" ); document.write( "you meet at 5 PM
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "We can confirm this by finding the distance that each traveled
\n" ); document.write( "40(5) = 200 mi
\n" ); document.write( "60(3) = 180 mi, (left 2 hrs later)
\n" ); document.write( "----------------
\n" ); document.write( "total = 380 mi
\n" ); document.write( ":
\n" ); document.write( "Did this make sense to you now? \n" ); document.write( "
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