document.write( "Question 539577: Natalie mixed 11 oz. of peanuts with 9 oz. of mixed nuts containing 60% peanuts. Peanuts are what percent of the new mixture?\r
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Algebra.Com's Answer #353471 by mananth(16946)\"\" \"About 
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--------percent ---------------- quantity
\n" ); document.write( "peanuts 100 ---------------- 11 Oz
\n" ); document.write( "mixed nuts 60 ---------------- x Oz
\n" ); document.write( "Mixture 90 ---------------- 11 + x Oz
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\n" ); document.write( "100*11+ 60x=90(11+x)
\n" ); document.write( "1100 +60x =990 +90x
\n" ); document.write( "60x+ -90x = 990- -1100
\n" ); document.write( "-30 x = -110
\n" ); document.write( "/ -30
\n" ); document.write( "x = 3.67
\n" ); document.write( "3.67 Oz of mixed nuts
\n" ); document.write( "Peanuts = (11-3.67)= 7.33 Oz\r
\n" ); document.write( "\n" ); document.write( "Percentage of peanuts = ((7.33)/(14.67)) * 100 = 49.97
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