document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=539566>Question 539566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm having trouble coming up with the asnwer to: log base 2 2x + log base 2 (x+3) = 3. I'd really appreciate a step by step walkthrough thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353467 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353467\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log2(2x) + log2(x+3) = 3<BR>\n" );
document.write( "------<BR>\n" );
document.write( "log2[2x(x+3)] = 3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "2x(x+3) = 2^3<BR>\n" );
document.write( "---<BR>\n" );
document.write( "2x^2+6x-8 = 0<BR>\n" );
document.write( "x^2+3x-4 = 0<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "(x+4)(x-1) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = 1<BR>\n" );
document.write( "============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );