document.write( "Question 539568: A whale swimming against an ocean current traveled 60 mi in 2 h. Swimming in the opposite direction, with the current, the wahel was able to travel the same distance in 1.5 h. Find the speed of the whale in calm water and the rate of the ocean current. \n" ); document.write( "
Algebra.Com's Answer #353466 by mananth(16946)\"\" \"About 
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Whale speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current , x-y 2 hours
\n" ); document.write( "with current , x+y 1.5 hours
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\n" ); document.write( "Distance = same= 60 miles
\n" ); document.write( "t=d/r
\n" ); document.write( "60 / ( x - y )= 2.00
\n" ); document.write( "2 ( x - y ) = 60.00
\n" ); document.write( "2 x -2 y = 60 ....................1
\n" ); document.write( "60 / ( x + y )= 1.50
\n" ); document.write( "1.50 ( x + y ) = 60
\n" ); document.write( "1.50 x + 1.50 y = 60 ...............2
\n" ); document.write( "Multiply (1) by 3.00
\n" ); document.write( "Multiply (2) by 4.00
\n" ); document.write( "we get
\n" ); document.write( "6 x + -6 y = 180
\n" ); document.write( "6 x + 6 y = 240
\n" ); document.write( "12 x = 420
\n" ); document.write( "/ 12
\n" ); document.write( "x = 35 mph
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\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "2 x -2 y = 60
\n" ); document.write( "70 -2 y = 60
\n" ); document.write( "-2 y = 60 -70
\n" ); document.write( "-2 y = -10
\n" ); document.write( " y = 5 mph
\n" ); document.write( " Whale 35 mph
\n" ); document.write( " current 5 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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