document.write( "Question 539555: a plane left an airport and flew with the wind for 4 hours, covering 2,000 kilometers. it then returned over the same route against the same wind in 5 hours. find the rate of the plane in still air and the speed of the wind. \n" ); document.write( "
Algebra.Com's Answer #353460 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! a = airspeed of the plane in calm air \n" ); document.write( "w = wind speed \n" ); document.write( ". \n" ); document.write( "ground speed with a tailwind = a+w \n" ); document.write( "ground speed with a headwind = a-w \n" ); document.write( ". \n" ); document.write( "d = 2000 km \n" ); document.write( ". \n" ); document.write( "(a+w) *4 hr = 2000 km \n" ); document.write( "a+w = 500 km/hr \n" ); document.write( ". \n" ); document.write( "(a-w) *5 hr = 2000 km \n" ); document.write( "a-w = 400 km/hr \n" ); document.write( ". \n" ); document.write( "a + w = 500 \n" ); document.write( "a - w = 400 \n" ); document.write( "------------ \n" ); document.write( "2a = 900 \n" ); document.write( "a = 450 \n" ); document.write( ". \n" ); document.write( "a+w = 500 \n" ); document.write( "w = 50 \n" ); document.write( ". \n" ); document.write( "Check the distances traveled over the given times. \n" ); document.write( "(450+50) km/hr * 4 hr = 2000 km \n" ); document.write( "(450-50) km/hr * 5 hr = 2000 km \n" ); document.write( "Correct \n" ); document.write( ". \n" ); document.write( "Answer: The rate of the plane in calm air is 450 km/hr. The wind speed is 50 km/hr. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |