document.write( "Question 539538: A truck and a car leave an intersection at the same time traveling in the same direction. The
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document.write( "truck’s speed is 30 mph, and the speed of the car is 35 mph. After how long will the car be 5 miles ahead of the truck? \n" );
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Algebra.Com's Answer #353456 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! d = r*t, where d=distance, r=rate, and t=time. \n" ); document.write( "so \n" ); document.write( "t = d/r \n" ); document.write( ". \n" ); document.write( "Truck: \n" ); document.write( "r = 30 mph \n" ); document.write( "d = x miles \n" ); document.write( "t = x/30 \n" ); document.write( ". \n" ); document.write( "Car: \n" ); document.write( "r = 35 mph \n" ); document.write( "d = x+5 miles \n" ); document.write( "t = (x+5)/35 \n" ); document.write( ". \n" ); document.write( "t = t \n" ); document.write( "so \n" ); document.write( "x/30 = (x+5)/35 \n" ); document.write( ". \n" ); document.write( "Cross multiply. \n" ); document.write( ". \n" ); document.write( "35x = 30(x+5) \n" ); document.write( "35x = 30x + 150 \n" ); document.write( "5x = 150 \n" ); document.write( "x = 30 miles \n" ); document.write( ". \n" ); document.write( "t = 30 miles/30 mph = 1 hr \n" ); document.write( "@ 30 mph it takes 1 hr to travel 30 miles \n" ); document.write( ". \n" ); document.write( "Checking \n" ); document.write( "t = 35 miles/35 mph = 1 hr \n" ); document.write( "@ 35 mph it takes 1 hr to travel 35 miles \n" ); document.write( ". \n" ); document.write( "So, the car will be 5 miles ahead in 1 hr. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |