document.write( "Question 539541: A man rows 18 miles downstream in 2 hours. He finds that it takes 8 hours to row back. Find the rate of the rowing to still water and the rate of the streets\r
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document.write( "please show steps! it'd help a lot, thanks :D \n" );
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Algebra.Com's Answer #353452 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Boat speed =x mph \n" ); document.write( "current speed =y mph \n" ); document.write( "against current x-y 8.00 hours \n" ); document.write( "With current x+y 2.00 hours \n" ); document.write( " \n" ); document.write( "Distance = same= 18 miles \n" ); document.write( "t=d/r \n" ); document.write( "18 / ( x - y )= 8.00 \n" ); document.write( "8 ( x - y ) = 18.00 \n" ); document.write( "8 x -8 y = 18 ....................1 \n" ); document.write( "18 / ( x + y )= 2.00 \n" ); document.write( "2.00 ( x + y ) = 18 \n" ); document.write( "2.00 x + 2.00 y = 18 ...............2 \n" ); document.write( "Multiply (1) by 1.00 \n" ); document.write( "Multiply (2) by 4.00 \n" ); document.write( "we get \n" ); document.write( "8 x + -8 y = 18 \n" ); document.write( "8 x + 8 y = 72 \n" ); document.write( "16 x = 90 \n" ); document.write( "/ 16 \n" ); document.write( "x = 5.63 mph \n" ); document.write( " \n" ); document.write( "plug value of x in (1) \n" ); document.write( "8 x -8 y = 18 \n" ); document.write( "45 -8 y = 18 \n" ); document.write( "-8 y = 18 -45 \n" ); document.write( "-8 y = -27 \n" ); document.write( " y = 3.38 mph \n" ); document.write( " Boat 5.63 mph \n" ); document.write( " current 3.38 mph \r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |