document.write( "Question 539517: Candy worth $3.25 a pound was mixed with candy worth $2.70 a pound. How many pounds of each were used if there was three times as much of the $2.70 as the #3.25 candy and if the value of the mixture was $90.80. \n" ); document.write( "

Algebra.Com's Answer #353446 by oberobic(2304) $\"\"$ $\"About$

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x = pounds of candy at $3.25 per pound
\n" ); document.write( "325x = value of the candy in cents
\n" ); document.write( "y = pounds of candy at $2.70 per pound
\n" ); document.write( "270y = value of candy in cents
\n" ); document.write( "325x + 270y = 9080 cents
\n" ); document.write( "y = 3x (given)
\n" ); document.write( ".
\n" ); document.write( "substitute
\n" ); document.write( ".
\n" ); document.write( "325x + 270(3x) = 9080
\n" ); document.write( "325x + 810x = 9080
\n" ); document.write( "1135x = 9080
\n" ); document.write( "x = 8 lb of candy valued at $3.25/lb
\n" ); document.write( ".
\n" ); document.write( "y = 3x
\n" ); document.write( "y = 24 lb of candy valued at $2.70/lb
\n" ); document.write( ".
\n" ); document.write( "Check the total value.
\n" ); document.write( "8*3.25 + 24*2.70 = ??
\n" ); document.write( "8*3.25 + 24*2.70 = 90.80
\n" ); document.write( "Correct.
\n" ); document.write( ".
\n" ); document.write( "Answer: 8 lb of $3.25/lb candy + 24 lb of $2.70/lb candy were mixed.
\n" ); document.write( ".
\n" ); document.write( "Done. \n" ); document.write( "

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