document.write( "Question 52995: 2+4+6+...+34
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document.write( "------------- = ?
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document.write( "3+6+9+...+51
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document.write( " In this problem, instead of adding the numbers one by one is there any short method?
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document.write( " Thank you. \n" );
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Algebra.Com's Answer #35344 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! 2+4+6+...+34 \n" ); document.write( "------------- = ? \n" ); document.write( "3+6+9+...+51 \n" ); document.write( "In this problem, instead of adding the numbers one by one is there any short method? \n" ); document.write( "these are called arithmatic serties when difference between 2 consecutive numbers is constant..here 4-2=6-4=2....=34-32 \n" ); document.write( "there is formula to find the sum in such cases.but if you are not taught that there is a simple trick you cn use. \n" ); document.write( "we have to find \n" ); document.write( "s=2 + 4 + 6+8+.........+30+32+34........now write them in reverse order \n" ); document.write( "s=34+32 +30+28+........+6 + 4 +2........now add \n" ); document.write( "----------------------------------------------------- \n" ); document.write( "2s=36+36+36+36+........+36+36+36=36*17 times \n" ); document.write( "s=36*17/2=306 \n" ); document.write( "i think you can now do the second problem by your self \n" ); document.write( " |