document.write( "Question 539493: THE factor polynomial problem is 15x2−84x−36\r
\n" ); document.write( "\n" ); document.write( "I know the answer to the polynomial is 3(5x+2)(x−6)but i dont understand how you get from \r
\n" ); document.write( "\n" ); document.write( "3(5x2−28x−12)to 3(5x+2)(x−6)<----the answer\r
\n" ); document.write( "\n" ); document.write( "can you please show me how you get it STEP BY STEP\r
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Algebra.Com's Answer #353432 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"15x%5E2-84x-36\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"3%285x%5E2-28x-12%29\" Factor out the GCF \"3\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's try to factor the inner expression \"5x%5E2-28x-12\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"5x%5E2-28x-12\", we can see that the first coefficient is \"5\", the second coefficient is \"-28\", and the last term is \"-12\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"5\" by the last term \"-12\" to get \"%285%29%28-12%29=-60\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-60\" (the previous product) and add to the second coefficient \"-28\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-60\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-60\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,5,6,10,12,15,20,30,60\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-60\".\r
\n" ); document.write( "\n" ); document.write( "1*(-60) = -60
\n" ); document.write( "2*(-30) = -60
\n" ); document.write( "3*(-20) = -60
\n" ); document.write( "4*(-15) = -60
\n" ); document.write( "5*(-12) = -60
\n" ); document.write( "6*(-10) = -60
\n" ); document.write( "(-1)*(60) = -60
\n" ); document.write( "(-2)*(30) = -60
\n" ); document.write( "(-3)*(20) = -60
\n" ); document.write( "(-4)*(15) = -60
\n" ); document.write( "(-5)*(12) = -60
\n" ); document.write( "(-6)*(10) = -60\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-28\":\r
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First NumberSecond NumberSum
1-601+(-60)=-59
2-302+(-30)=-28
3-203+(-20)=-17
4-154+(-15)=-11
5-125+(-12)=-7
6-106+(-10)=-4
-160-1+60=59
-230-2+30=28
-320-3+20=17
-415-4+15=11
-512-5+12=7
-610-6+10=4
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"2\" and \"-30\" add to \"-28\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"2\" and \"-30\" both multiply to \"-60\" and add to \"-28\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-28x\" with \"2x-30x\". Remember, \"2\" and \"-30\" add to \"-28\". So this shows us that \"2x-30x=-28x\".\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2%2Bhighlight%282x-30x%29-12\" Replace the second term \"-28x\" with \"2x-30x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%285x%5E2%2B2x%29%2B%28-30x-12%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%285x%2B2%29%2B%28-30x-12%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%285x%2B2%29-6%285x%2B2%29\" Factor out \"6\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-6%29%285x%2B2%29\" Combine like terms. Or factor out the common term \"5x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "So \"3%285x%5E2-28x-12%29\" then factors further to \"3%28x-6%29%285x%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"15x%5E2-84x-36\" completely factors to \"3%28x-6%29%285x%2B2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"15x%5E2-84x-36=3%28x-6%29%285x%2B2%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"3%28x-6%29%285x%2B2%29\" to get \"15x%5E2-84x-36\" or by graphing the original expression and the answer (the two graphs should be identical).\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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