document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=539467>Question 539467</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary if their sum is 180. One angle measures two times the measure of a smaller angle. If x represents the smaller angle and these two angles are supplementary, find the measure of each angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353429 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary if their sum is 180. One angle measures two times the measure of a smaller angle. If x represents the smaller angle and these two angles are supplementary, find the measure of each angle. <BR>\n" );
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document.write( "smaller = x<BR>\n" );
document.write( "supplement = 180-x<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "180-x = 2x<BR>\n" );
document.write( "180 = 3x<BR>\n" );
document.write( "x = 60 (smaller)<BR>\n" );
document.write( "180-x = 120 (larger)<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );