document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52985>Question 52985</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5(x – 1) = 3x + 8  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35342 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5(x – 1) <BR>\n" );
document.write( "This implies that every term with the brackets(in this case x and -1) should be multiplied with every term immediately outside the bracket(in this case 5)\r<BR>\n" );
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document.write( "So you get 5x -5<BR>\n" );
document.write( "5x -5 = 3x + 8 \r<BR>\n" );
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document.write( "Subtracting 3x on both sides<BR>\n" );
document.write( "2x-5 = 8\r<BR>\n" );
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document.write( "Adding 5 on both sides<BR>\n" );
document.write( "2x = 13\r<BR>\n" );
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document.write( "Dividing by 2 on both sides<BR>\n" );
document.write( "X = 13/2\r<BR>\n" );
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document.write( "This is you answer :-) </SPAN>\n" );
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