document.write( "Question 539307: A man wants to blend 30kg of coffee and each kilo cost $4.80.
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Algebra.Com's Answer #353407 by AnlytcPhil(1806)\"\" \"About 
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A man wants to blend 30kg of coffee and each kilo cost $4.80.
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document.write( "Suppose we mix x kg of the $6 coffee with y kg of the $4 coffee.\r\n" );
document.write( "Then we have two equations, a coffee equation and a money equation:\r\n" );
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document.write( "The coffee equation comes from\r\n" );
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document.write( "         \"%28matrix%286%2C1%2Cx%2C+kgs%2C+of%2C+more%2C+expensive%2C+coffee%29%29\" + \"%28matrix%286%2C1%2Cy%2C+kgs%2C+of%2C+less%2C+expensive%2Ccoffee%29%29\" = \"%28matrix%287%2C1%2C30%2C+kgs%2C+of%2C+medium%2C+priced%2C+mixed%2C+coffee%29%29\"  \r\n" );
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document.write( "                          x + y = 30\r\n" );
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document.write( "The money equation comes from\r\n" );
document.write( "    \r\n" );
document.write( "          + \"%28matrix%288%2C1%2C%22%244%22%2C+times%2Cy%2C+kgs%2C+of%2C+less%2C+expensive%2Ccoffee%29%29\" =   \r\n" );
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document.write( "                        $6x + $4y = ($4.80)(30)\r\n" );
document.write( "                          6x + 4y = 144\r\n" );
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document.write( "So solve this system of equations:\r\n" );
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document.write( "                         x +  y =  30\r\n" );
document.write( "                        6x + 4y = 144\r\n" );
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document.write( "Answer: Mix 12 kgs of the more expensive coffee and 18 kgs of the cheaper coffee\r\n" );
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document.write( "Edwin
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