document.write( "Question 539272: In a race, if a dog going 37 mph gets a headstart of 12 yards, how long will it take a dog going 38 mph to catch up? \n" ); document.write( "
| Algebra.Com's Answer #353379 by stanbon(75887)      You can put this solution on YOUR website! In a race, if a dog going 37 mph gets a headstart of 12 yards, how long will it take a dog going 38 mph to catch up? \n" ); document.write( "--- \n" ); document.write( "12 yds = 12/1760 = 0.0068 miles \n" ); document.write( "-------------------- \n" ); document.write( "1st dog DATA: \n" ); document.write( "rate = 37 mph ; distance = x miles ; time = x/37 hrs \n" ); document.write( "---- \n" ); document.write( "2nd dog DATA: \n" ); document.write( "rate = 38 mph ; distance = x+0.0068 miles; time = (x+0.0068)/38 hrs \n" ); document.write( "======================== \n" ); document.write( "Equation: \n" ); document.write( "time = time \n" ); document.write( "x/37 = (x+0.0068)/38 \n" ); document.write( "38x = 37x + 37*0.0068 \n" ); document.write( "x = 0.2516 miles \n" ); document.write( "--- \n" ); document.write( "time = x/37 = 0.2516/37 = 0.0068 hrs = 0.4080 minutes \n" ); document.write( "========================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |