document.write( "Question 539195: A circle is Defined by the following equation,
\n" ); document.write( "3x^2+3y^2-30x+27=0.
\n" ); document.write( "what is the radius?
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Algebra.Com's Answer #353366 by htmentor(1343)\"\" \"About 
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The equation for a circle in standard form is:
\n" ); document.write( "(x-a)^2 + (y-b)^2 = R^2
\n" ); document.write( "First, we can divide through by 3 which gives:
\n" ); document.write( "x^2 + y^2 - 10x + 9 = 0
\n" ); document.write( "In this case, we know b=0 since there is no linear term in y
\n" ); document.write( "The coefficient of the linear x term is -10, which is obtained from (x-5)(x-5)
\n" ); document.write( "So we can write
\n" ); document.write( "(x-5)^2 + y^2 = R^2
\n" ); document.write( "x^2 - 10x + 25 - R^2 + y^2 = 0 <-> x^2 - 10x + 9 + y^2 = 0
\n" ); document.write( "This means 25 - R^2 = 9 -> R^2 = 16
\n" ); document.write( "So the radius, R = 4
\n" ); document.write( "And the equation in standard form is:
\n" ); document.write( "(x-5)^2 + y^2 = 16
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