document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=539110>Question 539110</A>: <I><SPAN STYLE=\"word-break: break-all;\"> twise a number added to 3 times itself is equal to 90.find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353331 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathpassionate><B>Mathpassionate(25)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathpassionate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Mathpassionate><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> twice a number added to 3 times itself is equal to 90.find the number.\r<BR>\n" );
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document.write( "Let N = number\r<BR>\n" );
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document.write( "twice a number = 2N\r<BR>\n" );
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document.write( "3 times itself = 3N\r<BR>\n" );
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document.write( "So,\r<BR>\n" );
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document.write( "twice a number added to 3 times itself is equal to 90\r<BR>\n" );
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document.write( "2N+3N = 90<BR>\n" );
document.write( "5N = 90\r<BR>\n" );
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document.write( "N =90/5\r<BR>\n" );
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document.write( "N = 18\r<BR>\n" );
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document.write( "The answer is 18.\r<BR>\n" );
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document.write( "Any question, please ask me. My email is AREVALOGABRIEL2@GMAIL.COM<BR>\n" );
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