document.write( "Question 539115: Find the error in this proof that 2=1.
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document.write( " x=y
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document.write( " X^2=xy
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document.write( " X^2-y^2=xy-y^2
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document.write( " (x+y)(x-y)=y(x-y)
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document.write( " ((x+y)(x-y)/(x-y))=(y(x-y)/(x-y))
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document.write( " X+y=y
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document.write( " Y+y=y
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document.write( " 2y=y
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document.write( " (2y/y)=(y/y)
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document.write( " 2=1
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document.write( "
Algebra.Com's Answer #353329 by Mathpassionate(25)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The error is here:\r \n" ); document.write( "\n" ); document.write( "((x+y)(x-y)/(x-y))=(y(x-y)/(x-y))\r \n" ); document.write( "\n" ); document.write( "Because we know that x=y\r \n" ); document.write( "\n" ); document.write( "So x-y = 0\r \n" ); document.write( "\n" ); document.write( "And we cannot divide by zero.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |