document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=539008>Question 539008</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the point on the y-axis that is equidistant from (5,1) and (-3,-1). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353308 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353308\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the point on the y-axis that is equidistant from (5,1) and (-3,-1)<BR>\n" );
document.write( "**<BR>\n" );
document.write( "distance formula:<BR>\n" );
document.write( "d^2=(x1-x2)^2+(y1-y2)^2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "d1^2=d2^2<BR>\n" );
document.write( "(x-5)^2+(y-1)^2=(x+3)^2+(y+1)^2<BR>\n" );
document.write( "x-coordinate of point on y-axis=0<BR>\n" );
document.write( "(0-5)^2+(y-1)^2=(0+3)^2+(y+1)^2<BR>\n" );
document.write( "25+y^2-2y+1=9+y^2+2y+1<BR>\n" );
document.write( "-4y=-16<BR>\n" );
document.write( "4y=16<BR>\n" );
document.write( "y=4<BR>\n" );
document.write( "..<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "Point on the y-axis=4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );