document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=538970>Question 538970</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me on this problem: Solve the linear system using the substitution method.<BR>\n" );
document.write( "x=16-4y<BR>\n" );
document.write( "3x+4y=8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353298 by </B><A HREF=/tutors/aboutme.mpl?userid=boilpoil><B>boilpoil(127)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=boilpoil><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=boilpoil><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=16-4y<BR>\n" );
document.write( "3x+4y=8 ---Since x is already the subject, we'll substitute x into second equation\r<BR>\n" );
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document.write( "3(16-4y)+4y=8<BR>\n" );
document.write( "48-12y+4y=8<BR>\n" );
document.write( "-8y=-40<BR>\n" );
document.write( "y=5\r<BR>\n" );
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document.write( "x=16-4(5)<BR>\n" );
document.write( "x=16-20<BR>\n" );
document.write( "x=-4 </SPAN>\n" );
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