document.write( "Question 538917: The current I in an electrical conductor varies inversely as the resistance R of the conductor. If the current is 0.5 amperes when the resistance is 240 ohms, what is the current when the resistance is 960 ohms? \n" ); document.write( "

Algebra.Com's Answer #353286 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
You could start with Ohm's law:
\n" ); document.write( " $\"E+=+I%2AR\"$ Solve for I.
\n" ); document.write( " $\"I+=+E%2FR\"$ Substitute I = 0.5 amps. and R = 240 ohms.
\n" ); document.write( " $\"0.5+=+E%2F240\"$ Solve for E.
\n" ); document.write( " $\"E+=+0.5%28240%29\"$
\n" ); document.write( " $\"E+=+120\"$ Now Ohm's law looks like:
\n" ); document.write( " $\"I+=+120%2FR\"$ Substitute R = 960 ohms.
\n" ); document.write( " $\"I+=+120%2F960\"$ Evaluate.
\n" ); document.write( " $\"I+=+0.125\"$ amperes. \n" ); document.write( "

\n" );