document.write( "Question 538928: (2x-5)^2= 81 \n" ); document.write( "
Algebra.Com's Answer #353284 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"%282x-5%29%5E2=81\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-5=%22%22%2B-sqrt%2881%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-5=sqrt%2881%29\" or \"2x-5=-sqrt%2881%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-5=9\" or \"2x-5=-9\" Take the square root of \"81\" to get \"9\".\r
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\n" ); document.write( "\n" ); document.write( "\"2x=5%2B9\" or \"2x=5-9\" Add \"5\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=14\" or \"2x=-4\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x=7\" or \"x=-2\" Divide both sides by \"2\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=7\" or \"x=-2\".\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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