document.write( "Question 538891: Please help me solve this :
\n" ); document.write( "Find the mean for the following probability distribution, where x = number of hurricanes that hit a certain coast area in any given year and P(x) = the corresponding probabilities.
\n" ); document.write( " x P(x)
\n" ); document.write( " 0 .15
\n" ); document.write( " 1 .4
\n" ); document.write( " 2 .3
\n" ); document.write( " 3 .15
\n" ); document.write( "I think I would go X = 4 and P(x)=.37 q= 1-.37 =.63
\n" ); document.write( "and .63 would be my mean but im not sure if i have to find mean that is
\n" ); document.write( "0+.15 /2 = .075
\n" ); document.write( "1+.4=.7 and so on
\n" ); document.write( "Thanks for you help \n" ); document.write( "

Algebra.Com's Answer #353275 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
Mean = sum of the x*P(x) terms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Mean = 0*0.15 + 1*0.4 + 2*0.3 + 3*0.15\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Mean = 0 + 0.4 + 0.6 + 0.45\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Mean = 1.45\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the mean is 1.45 \n" ); document.write( "

\n" );