document.write( "Question 538840: a freight train left pennsylvania station traveling at 35mph. two hours later, a highspeed train left pennsylvania station on parallel tracks traveling 55mph. In how many hours after the slow train starts will the two trains meet? \n" ); document.write( "
Algebra.Com's Answer #353261 by ankor@dixie-net.com(22740)\"\" \"About 
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a freight train left pennsylvania station traveling at 35mph. two hours later, a highspeed train left pennsylvania station on parallel tracks traveling 55mph.
\n" ); document.write( " In how many hours after the slow train starts will the two trains meet?
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\n" ); document.write( "Let t = travel time of the freight
\n" ); document.write( "then
\n" ); document.write( "(t-2) = travel time of fast train
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\n" ); document.write( "When the fast train catches the freight, they will have traveled the same distance
\n" ); document.write( "Write a dist equation, dist = speed * time
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\n" ); document.write( "fast dist = slow dist
\n" ); document.write( "55(t-2) = 35t
\n" ); document.write( "55t - 110 = 35t
\n" ); document.write( "55t - 35t = 110
\n" ); document.write( "20t = 110
\n" ); document.write( "t = 110/20
\n" ); document.write( "t = 5.5 hrs for the freight to be caught
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\n" ); document.write( "Check this by finding the distance of each, should be the same
\n" ); document.write( "35*5.5 = 192.5 mi
\n" ); document.write( "55*3.5 = 192.5 \n" ); document.write( "
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