document.write( "Question 538672: Find the equation of the circle of radius 2 that contains point (3,4) and is tangent to x^2+y^2=25. \n" ); document.write( "
Algebra.Com's Answer #353239 by KMST(5328)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The point (3,4) belongs to that circle and is the only point in common with the tangent circle(s). The circles are tangent at that point. \n" ); document.write( "However, we have two choices: the circles could be externally tangent or internally tangent. \n" ); document.write( "In either case, at (3,4), the radius of the given circle and the radius of the tangent circle are on the same line, a line that passes through (0,0) and (3,4). The center of the tangent circle(s) is (are) on that line at a distance of 2 from (3,4). \n" ); document.write( "We could find the coordinates of the center(s) in different ways. I can think of solving equations involving distance, invoking sine and cosine of the angle of that radius with the positive x-axis, or considering similar right triangles. \n" ); document.write( "I used the last option to find centers at (9/5, 12/5) and at (21/5, 28/5). The centers are at the top of the red and green lines in the figure below. \n" ); document.write( " \n" ); document.write( "The side ratios \n" ); document.write( "vertical (colorful) leg/hypotenuse = 4/5 and \n" ); document.write( "horizontal leg/hypotenuse = 3/5 allowed me to calculate the coordinates of the centers for the red and green circles. \n" ); document.write( "The equation for the internally tangent red circle, centered at (9/5, 12/5) is \n" ); document.write( "The equation for the externally tangent green circle, centered at (21/5, 28/5) is |