document.write( "Question 538697: I Am really struggling on solving linear equations with substitution and elimination. could you help me out and tell me the most easiest way to do these \n" ); document.write( "
Algebra.Com's Answer #353230 by JLB(8)\"\" \"About 
You can put this solution on YOUR website!
This is an example of a linear equation : 2x + 4 = 10\r
\n" ); document.write( "\n" ); document.write( "2x + 4 = 10\r
\n" ); document.write( "\n" ); document.write( "The goal is to find what X is equal to, your final answer is X = (answer)
\n" ); document.write( "The first step in solving this equation is to subtract 4 from both sides. (Remember that what you do to one side you must do to both sides).\r
\n" ); document.write( "\n" ); document.write( "2x + 4 - 4 = 10 - 4\r
\n" ); document.write( "\n" ); document.write( "2x = 6\r
\n" ); document.write( "\n" ); document.write( "Now you just need to divide both sides by 2, and you will get the final answer:\r
\n" ); document.write( "\n" ); document.write( "x = 3\r
\n" ); document.write( "\n" ); document.write( "Let's do another one.\r
\n" ); document.write( "\n" ); document.write( "\"+x%2F3+-+12+=+36+\"\r
\n" ); document.write( "\n" ); document.write( "\"+x%2F3+-+12+%2B+12+=+36+%2B+12+\"\r
\n" ); document.write( "\n" ); document.write( "\"+x%2F3+=+48+\"\r
\n" ); document.write( "\n" ); document.write( "\"+x+=+16+\"\r
\n" ); document.write( "\n" ); document.write( "Do you see that? You need to do the opposite operation (subtracting and adding are opposite, division and multiplication are opposite) to both sides. So when you see x - 1 = 12, you know to add 1 to 12 to get 13, and to cancel out the x + 1 to get simply x. x = 13.\r
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