document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=538628>Question 538628</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 60 feet. the ratio of the width to the length is three to seven. find the area of this rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353221 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathpassionate><B>Mathpassionate(25)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathpassionate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Mathpassionate><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353221\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 60 feet. the ratio of the width to the length is three to seven. find the area of this rectangle\r<BR>\n" );
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document.write( "A = Area<BR>\n" );
document.write( "W = Width<BR>\n" );
document.write( "L = Length<BR>\n" );
document.write( "P = Perimeter\r<BR>\n" );
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document.write( "We know that:\r<BR>\n" );
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document.write( "1) A = L*W<BR>\n" );
document.write( "2) P = 2L + 2W\r<BR>\n" );
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document.write( "P = 60\r<BR>\n" );
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document.write( "W/L = 3/7\r<BR>\n" );
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document.write( "Work out the value of W.\r<BR>\n" );
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document.write( "W = 3L/7\r<BR>\n" );
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document.write( "Now, let's substitute  W = 3L/7 into the equation P = 2L + 2W\r<BR>\n" );
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document.write( "P = 2L + 2W<BR>\n" );
document.write( "P = 2L + 2*(3L/7)<BR>\n" );
document.write( "P = 2L + 6L/7\r<BR>\n" );
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document.write( "We know that P = 60\r<BR>\n" );
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document.write( "P = 2L + 6L/7<BR>\n" );
document.write( "60 = 2L + 6L/7<BR>\n" );
document.write( "60 = 14L/7 + 6L/7<BR>\n" );
document.write( "60 = (14L+6L)/7<BR>\n" );
document.write( "60 = (20L)/7<BR>\n" );
document.write( "60*7 = 20L<BR>\n" );
document.write( "(60*7)/20 = L<BR>\n" );
document.write( "3*7 = L<BR>\n" );
document.write( "21 = L\r<BR>\n" );
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document.write( "Now, let's substitute  L =21 into the equation W = 3L/7\r<BR>\n" );
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document.write( "W = 3L/7<BR>\n" );
document.write( "W = 3*21/7<BR>\n" );
document.write( "W = 3*3<BR>\n" );
document.write( "W = 9\r<BR>\n" );
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document.write( "Now using:\r<BR>\n" );
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document.write( "A = L*W<BR>\n" );
document.write( "A = 21*9<BR>\n" );
document.write( "A = 189\r<BR>\n" );
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document.write( "The answer is:\r<BR>\n" );
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document.write( "The area of the rectangle is 189 Square feet.\r<BR>\n" );
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document.write( "If you have any questions, please let me know.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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