document.write( "Question 538177: ann has 3 times as many beads as marie, ann gives marie 55 beads, now ann has half as many beads as marie. how many beads are all together? \n" ); document.write( "
Algebra.Com's Answer #353220 by ankor@dixie-net.com(22740)\"\" \"About 
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ann has 3 times as many beads as marie, ann gives marie 55 beads,
\n" ); document.write( " now ann has half as many beads as marie.
\n" ); document.write( " how many beads are all together?
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\n" ); document.write( "a = 3m
\n" ); document.write( "Gives 55, now
\n" ); document.write( "(a-55) for Ann
\n" ); document.write( "(m+55) for Marie
\n" ); document.write( ":
\n" ); document.write( "\"now ann has half as many beads as marie.\"
\n" ); document.write( "(a-55) = .5(m+55)
\n" ); document.write( "a - 55 = .5m + 27.5
\n" ); document.write( "a = .5m + 27.5 + 55
\n" ); document.write( "a = .5m + 82.5
\n" ); document.write( "replace a with 3m
\n" ); document.write( "3m = .5m + 82.5
\n" ); document.write( "3m - .5 = 62.5
\n" ); document.write( "2.5m = 82.5
\n" ); document.write( "m = 82.5/2.5
\n" ); document.write( "m = 33 beads originally for Marie
\n" ); document.write( "and
\n" ); document.write( "3(33) = 99 beads originally for Ann
\n" ); document.write( "then
\n" ); document.write( "33 + 99 = 132 total beads
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