document.write( "Question 538566: how do you write an equation for the line in slope-intercept form that is parallel to the given line and passes through the given point?\r
\n" ); document.write( "\n" ); document.write( "y = -2x + 6; (0,1)
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Algebra.Com's Answer #353203 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The given line is in the slope-intercept form
\n" ); document.write( "which is: \"+y+=+m%2Ax+%2B+b+\", where \"m\" = slope,
\n" ); document.write( "\"+y+=+-2x+%2B+6+\"
\n" ); document.write( "The slope is \"-2\", and all line parallel to this
\n" ); document.write( "line will also have slope = \"-2\"
\n" ); document.write( "So far I have: \"+y+=+-2x+%2B+b+\"
\n" ); document.write( "Now plug in (x,y) = (0,1) to find \"b\"
\n" ); document.write( "\"+1+=+-2%2A0+%2B+b+\"
\n" ); document.write( "\"+b+=+1+\"
\n" ); document.write( "The equation is \"+y+=+-2x+%2B+1+\"
\n" ); document.write( "Here's a plot of the 2 lines:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+-2x+%2B+6%2C+-2x+%2B+1%29+\"
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