document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=538412>Question 538412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi i need help solving this problems: log5^1/25, log5^125, log3^1/9, log5^1/25+log5^25-log5^125 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353171 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You need to know that \"log\" means power or exponent.<BR>\n" );
document.write( "-----\r<BR>\n" );
document.write( "\n" );
document.write( "log5^1/25 = -2<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "log5^125 = 3<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "log3^1/9 = -2<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "log5^1/25+log5^25-log5^125<BR>\n" );
document.write( "= -2+2-3 <BR>\n" );
document.write( "= -3<BR>\n" );
document.write( "=========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "========= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );