document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=538403>Question 538403</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am not really sure how to go about beginning to solve this and could use some help please.\r<BR>\n" );
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document.write( "Simplify\r<BR>\n" );
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document.write( "eln (0.2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353168 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353168\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simplify <BR>\n" );
document.write( "e^(ln (0.2))<BR>\n" );
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document.write( "You have to understand that ln(0.2) is \"the<BR>\n" );
document.write( "power of e that gives you 0.2\"<BR>\n" );
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document.write( "You are asked to raise \"e\" to that power.<BR>\n" );
document.write( "--<BR>\n" );
document.write( "The results is e^(ln(0.2)) = 0.2<BR>\n" );
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document.write( "The problem is similar to \"What is the color of a red coat?\"<BR>\n" );
document.write( "The answer is \"red\".<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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