document.write( "Question 537951: What is the graph of this functions?
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document.write( "y= 1/2x^2 -3x+11/2\r
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document.write( "y= -2x^2+4x+3 \n" );
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Algebra.Com's Answer #353120 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! What is the graph of this functions? \n" ); document.write( ".. \n" ); document.write( "Problem 1. \n" ); document.write( "y= 1/2x^2 -3x+11/2 \n" ); document.write( "complete the square \n" ); document.write( "y=(1/2)(x^2-6x+9)+11/2-9/2 \n" ); document.write( "y=(1/2)(x-3)^2+1 \n" ); document.write( "This is an equation of a parabola of standard form: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. Parabola opens upwards. \n" ); document.write( "For given equation: \n" ); document.write( "vertex: (3,1) \n" ); document.write( "A=1/2 \n" ); document.write( "x-intercepts \n" ); document.write( "set y=0 \n" ); document.write( "(1/2)(x-3)^2+1=0 \n" ); document.write( "(x-3)^2=-2 \n" ); document.write( "x-intercepts: none \n" ); document.write( ".. \n" ); document.write( "y-intercept \n" ); document.write( "set x=0 \n" ); document.write( "y=1/2x^2 -3x+11/2 \n" ); document.write( "y=11/2 \n" ); document.write( "Because the parabola is symmetrical about its axis of symmetry(x=3), this gives another point (6,11/2) \n" ); document.write( ".. \n" ); document.write( "With coordinates of the vertex, the y-intercept, point (6,11/2), no x-intercepts and the knowledge the parabola opens upwards, you should easily be able to graph given function \n" ); document.write( ".. \n" ); document.write( "Problem 2. \n" ); document.write( "y= -2x^2+4x+3 \n" ); document.write( "complete the square \n" ); document.write( "y=-2(x^2-2x+1)+3+2 \n" ); document.write( "y=-2(x-1)^2+5 \n" ); document.write( "This is an equation of a parabola of standard form: y=-A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. Parabola opens downwards. \n" ); document.write( "For given equation: \n" ); document.write( "vertex: (1,5) \n" ); document.write( "A=-2 \n" ); document.write( "x-intercepts \n" ); document.write( "set y=0 \n" ); document.write( "-2(x-1)^2+5=0 \n" ); document.write( "-2(x-1)^2=-5 \n" ); document.write( "(x-1)^2=5/2 \n" ); document.write( "take sqrt of both sides \n" ); document.write( "x-1=±√(5/2)≈±1.58 \n" ); document.write( "x=1±1.58 \n" ); document.write( "x=2.58 and -0.58 \n" ); document.write( ".. \n" ); document.write( "y-intercept \n" ); document.write( "set x=0 \n" ); document.write( "y=-2x^2+4x+3=3 \n" ); document.write( "Because the parabola is symmetrical about its axis of symmetry(x=1), this gives another point (2,3) \n" ); document.write( ".. \n" ); document.write( "With coordinates of the vertex, the y-intercept, point (2,3), x-intercepts, and the knowledge the parabola opens downwards, you should easily be able to graph given function. \n" ); document.write( ".. \n" ); document.write( "See the following graphs as visual checks on the answers: \n" ); document.write( "Because the parabola is symmetrical about its axis of symmetry(x=3), this gives another point (6,11/2) \n" ); document.write( "With coordinates of the vertex, the y-intercept, point (6,11/2) and the knowledge the parabola opens upwards, you should easily be able to graph given function. See graph below as a visual check on the answers. Red curve for problem 1 and green curve for problem 2 \n" ); document.write( ".. \n" ); document.write( " |