document.write( "Question 537930: I need STEPS on how to do this!
\n" ); document.write( "A boy ran to the store at 6 miles per hour, he walked back at 4 miles per hour. If the roundtrip took hom 10 minutes, how far is the store?
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Algebra.Com's Answer #353052 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Use the distance formula:
\n" ); document.write( "\"d+=+r%2At\" where: d = distance, r = rate(speed), and t = time of travel.
\n" ); document.write( "Going to the store:
\n" ); document.write( "\"d%5B1%5D+=+r%5B1%5D%2At%5B1%5D\" Substitute: \"r%5B1%5D+=+6\"
\n" ); document.write( "\"d%5B1%5D+=+6%2At%5B1%5D\"
\n" ); document.write( "Returning returning from the store:
\n" ); document.write( "\"d%5B2%5D+=+r%5B2%5D%2At%5B2%5D\" Substitute \"r+=+4\"
\n" ); document.write( "\"d%5B2%5D+=+4%2At%5B2%5D\"
\n" ); document.write( "Now the total time is \"t%5B1%5D%2Bt%5B2%5D+=+10\" so \"t%5B2%5D+=+10-t%5B1%5D\" and the distance to the store is the same as the distance back, so \"d%5B1%5D+=+d%5B2%5D\"
\n" ); document.write( "So now we can write:
\n" ); document.write( "\"6%2At%5B1%5D+=+4%2At%5B2%5D\" Substitute \"t%5B2%5D+=+10-t%5B1%5D\"
\n" ); document.write( "\"6%2At%5B1%5D+=+4%2810-t%5B1%5D%29\" Simplify and solve for \"t%5B1%5D\"
\n" ); document.write( "\"6%2At%5B1%5D+=+40-4%2At%5B1%5D\" Add \"4%2At%5B1%5D\" to both sides.
\n" ); document.write( "\"10%2At%5B1%5D+=+40\" Divide both sides by 10.
\n" ); document.write( "\"t%5B1%5D+=+4\" Now substitute this into the first equation and solve for \"d%5B1%5D\"
\n" ); document.write( "\"d%5B1%5D+=+6%2At%5B1%5D\" Substitute \"t%5B1%5D+=+4\"
\n" ); document.write( "\"d%5B1%5D+=+6%2A4\"
\n" ); document.write( "\"d%5B1%5D+=+24\"
\n" ); document.write( "The store is 24 miles away.
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