document.write( "Question 537712: I want to factorise this polynom\r
\n" ); document.write( "\n" ); document.write( "x^3 - 8\r
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\n" ); document.write( "\n" ); document.write( "The answer should be (x - 2 )(x^2 + 2x + 4)\r
\n" ); document.write( "\n" ); document.write( "I want to know the method please\r
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Algebra.Com's Answer #352960 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"x%5E3-8\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%29%5E3-%282%29%5E3\" Rewrite \"x%5E3\" as \"%28x%29%5E3\". Rewrite \"8\" as \"%282%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%28%28x%29%5E2%2B%28x%29%282%29%2B%282%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%28x%5E2%2B2x%2B4%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"x%5E3-8\" factors to \"%28x-2%29%28x%5E2%2B2x%2B4%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E3-8=%28x-2%29%28x%5E2%2B2x%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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