document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52923>Question 52923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1) write the equation of the circle with center at(2,1)and which passes thru the point (2,7)\r<BR>\n" );
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document.write( "2) write the equation of the circle with center at (-1,-2) and which passes thru the point(-1,2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35293 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) write the equation of the circle with center at(2,1)and which passes thru the point (2,7)<BR>\n" );
document.write( "STD.EQN.OF CIRCLE WITH CENTRE AS (H,K) AND RADIUS = R IS <BR>\n" );
document.write( "(X-H)^2 + (Y-K)^2 =R^2.............H=2.........K=1..........SO<BR>\n" );
document.write( "EQN.IS <BR>\n" );
document.write( "(X-2)^2+(Y-1)^2=R^2..IT PASSES THROUGH (2,7)..HENCE<BR>\n" );
document.write( "(2-2)^2+(7-1)^2=R^2=36<BR>\n" );
document.write( "HENCE EQN.OF CIRLE IS <BR>\n" );
document.write( "(X-2)^2+(Y-1)^2=36\r<BR>\n" );
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document.write( "2) write the equation of the circle with center at (-1,-2) and which passes thru the point(-1,2)<BR>\n" );
document.write( "DO BY SAME METHOD AS ABOVE </SPAN>\n" );
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