document.write( "Question 537423: how can i write x=y2-2y-15 in standard form and graph it \n" ); document.write( "
Algebra.Com's Answer #352915 by lwsshak3(11628)\"\" \"About 
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how can i write x=y2-2y-15 in standard form and graph it
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\n" ); document.write( "x=y2-2y-15
\n" ); document.write( "complete the square
\n" ); document.write( "x=(y^2-2y+1)-15-1
\n" ); document.write( "x=(y-1)^2-16
\n" ); document.write( "This is an equation of a parabola which opens rightwards of the standard form: x=A(y-k)^2+h, with (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "..
\n" ); document.write( "For given equation of a parabola:
\n" ); document.write( "vertex: (-16,1)
\n" ); document.write( "..
\n" ); document.write( "y-intercept:
\n" ); document.write( "set x=0
\n" ); document.write( "(y-1)^2-16=0
\n" ); document.write( "(y-1)^2=16
\n" ); document.write( "take sqrt of both sides
\n" ); document.write( "y-1=±√16=±4
\n" ); document.write( "y=1±4
\n" ); document.write( "y=5 or -3
\n" ); document.write( "..
\n" ); document.write( "x-intercept
\n" ); document.write( "set y=0
\n" ); document.write( "x=-15
\n" ); document.write( "..
\n" ); document.write( "You now have coordinates of the vertex, the y-intercepts, x-intercept and knowledge that it is a parabola that opens rightwards, information with which you should be able to graph the given function.
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