document.write( "Question 537448: i need to list the vertex, focus, and directrix of this parabola
\n" ); document.write( "(x+2) = -8(y-3)^2
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Algebra.Com's Answer #352914 by lwsshak3(11628)\"\" \"About 
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i need to list the vertex, focus, and directrix of this parabola
\n" ); document.write( "(x+2) = -8(y-3)^2
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\n" ); document.write( "Standard form of an equation for a parabola which opens leftwards: (y-k)^2=-4p(x-h), (h,k) being the (x,y) coordinates of the vertex.
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\n" ); document.write( "(x+2) = -8(y-3)^2
\n" ); document.write( "rewrite equation
\n" ); document.write( "(y-3)^2=-(1/8)(x+2)
\n" ); document.write( "vertex:(-2,3)
\n" ); document.write( "Axis of symmetry: y=3
\n" ); document.write( "4p=1/8
\n" ); document.write( "p=1/32
\n" ); document.write( "focus:(-2-(1/32,3)=[-(65/32),3] (p units from vertex on the axis of symmetry)
\n" ); document.write( "directrix: x=-63/32 (a vertical line p units from vertex on the axis of symmetry)
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