document.write( "Question 537448: i need to list the vertex, focus, and directrix of this parabola
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document.write( "(x+2) = -8(y-3)^2 \n" );
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Algebra.Com's Answer #352914 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! i need to list the vertex, focus, and directrix of this parabola \n" ); document.write( "(x+2) = -8(y-3)^2 \n" ); document.write( "** \n" ); document.write( "Standard form of an equation for a parabola which opens leftwards: (y-k)^2=-4p(x-h), (h,k) being the (x,y) coordinates of the vertex. \n" ); document.write( ".. \n" ); document.write( "(x+2) = -8(y-3)^2 \n" ); document.write( "rewrite equation \n" ); document.write( "(y-3)^2=-(1/8)(x+2) \n" ); document.write( "vertex:(-2,3) \n" ); document.write( "Axis of symmetry: y=3 \n" ); document.write( "4p=1/8 \n" ); document.write( "p=1/32 \n" ); document.write( "focus:(-2-(1/32,3)=[-(65/32),3] (p units from vertex on the axis of symmetry) \n" ); document.write( "directrix: x=-63/32 (a vertical line p units from vertex on the axis of symmetry) \n" ); document.write( " |