document.write( "Question 537542: what is the center and length of a circle with the equation 81x^2 + 81y^2 = 1? \n" ); document.write( "
Algebra.Com's Answer #352913 by lwsshak3(11628)\"\" \"About 
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what is the center and length of a circle with the equation 81x^2 + 81y^2 = 1?
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\n" ); document.write( "Standard form of an equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k) being the (x,y) coordinates of the center, r=radius.
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\n" ); document.write( "81x^2 + 81y^2 = 1
\n" ); document.write( "Divide by 81
\n" ); document.write( "x^2+y^2=1/81
\n" ); document.write( "center: (0,0)
\n" ); document.write( "radius: √(1/81)=1/9 (I assumed this what you meant by length of a circle)
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